What is the domain of f(x)=\sqrt[3]{x/(x-2)} ?

The domain of f(x)=\sqrt[3]{x/(x-2)} is x 2

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domain of f(x)=\sqrt[3]{x/(x-2)}

domain

x < 2 or x > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2

The function domain

x < 2 or x > 2

f (x) = 10 x - 2

f (x) = \frac{x ^{2} - x - 6}{x ^{2} - 4}

f (x) = \frac{x - 3}{2} + 3

\frac{3 x + 1}{x ^{3} - 5 x ^{2} + 6 x}

2^{x - 3} + 4

What is the domain of f(x)=\sqrt[3]{x/(x-2)} ?
The domain of f(x)=\sqrt[3]{x/(x-2)} is x<2\lor x>2