What is the domain of f(x)=(x-4)/(x^2+13x+36) ?

The domain of f(x)=(x-4)/(x^2+13x+36) is x -4

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domain of f(x)=(x-4)/(x^2+13x+36)

domain

f (x) = \frac{x - 4}{x ^{2} + 13 x + 36}

x < - 9 or - 9 < x < - 4 or x > - 4

Interval Notation

(- \infty, - 9) \cup (- 9, - 4) \cup (- 4, \infty)

Solution steps

Find undefined (singularity) points:

x = - 4, x = - 9

The function domain

x < - 9 or - 9 < x < - 4 or x > - 4

f (x) = \frac{( x - 3 )}{x ^{2} - 9}

\frac{1}{x + 25}

5 9 - x^{2}

- \frac{2 x}{( x ^{2} - 49 ) ^{2}}

What is the domain of f(x)=(x-4)/(x^2+13x+36) ?
The domain of f(x)=(x-4)/(x^2+13x+36) is x<-9\lor-9<x<-4\lor x>-4