What is the domain of y=(2x^3+x-3)/(x^2+1) ?

The domain of y=(2x^3+x-3)/(x^2+1) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(2x^3+x-3)/(x^2+1)

domain

y = \frac{2 x ^{3} + x - 3}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

g (x) = ln (x)

f (x) = 5 x - 30 + ln (21 - 3 x)

y = - (1 - x)^{2} + 3

∣ x ∣ + x

∣ x ∣ - 5

What is the domain of y=(2x^3+x-3)/(x^2+1) ?
The domain of y=(2x^3+x-3)/(x^2+1) is -infinity <x<infinity