What is the domain of sqrt((x^2-8)/4)+sqrt(9x^2+8) ?

The domain of sqrt((x^2-8)/4)+sqrt(9x^2+8) is x = 2sqrt(2)

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domain of sqrt((x^2-8)/4)+sqrt(9x^2+8)

domain

\frac{x ^{2} - 8}{4} + 9 x^{2} + 8

x \leq - 22 or x \geq 22

Interval Notation

(- \infty, - 22] \cup [22, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 22 or x \geq 22

The function domain

x \leq - 22 or x \geq 22

f (x) = 25 - x^{2} + - (x - 2)

f (x) = \frac{x ^{2} - 10}{x ^{2} - 9}

\frac{x ^{2}}{4 - x ^{2}}

y = 2 x - 2

f (x) = (- 2 x + 3)

What is the domain of sqrt((x^2-8)/4)+sqrt(9x^2+8) ?
The domain of sqrt((x^2-8)/4)+sqrt(9x^2+8) is x<=-2sqrt(2)\lor x>= 2sqrt(2)