What is the domain of (2x-1)/(x^2+x-12) ?

The domain of (2x-1)/(x^2+x-12) is x 3

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domain of (2x-1)/(x^2+x-12)

domain

\frac{2 x - 1}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

f (x) = - 2 (x - 1)^{2} + 5 = 0

f (x) = 16 x^{2} + 9 y - 64 x + 18 y - 71 = 0

\frac{1}{- x ^{2} + 3 x - 2}

f (x) = 3 x^{4} = 18 x^{2}

y = \frac{5 x - 26}{x + 2}

What is the domain of (2x-1)/(x^2+x-12) ?
The domain of (2x-1)/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3