What is the domain of 1/(2xsqrt(4+ln(x))) ?

The domain of 1/(2xsqrt(4+ln(x))) is x> 1/(e^4)

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domain of 1/(2xsqrt(4+ln(x)))

domain

\frac{1}{2 x 4 + ln ( x )}

x > \frac{1}{e ^{4}}

Interval Notation

(\frac{1}{e ^{4}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{4}}

Find undefined (singularity) points:

x = \frac{1}{e ^{4}}

Combine real regions and undefined points for final function domain

x > \frac{1}{e ^{4}}

\frac{x ^{2} - 3 x - 4}{x + 1}

f (x) = x - 1

f (x) = \frac{2 x + 7}{x ^{2} + x - 6}

f (x) = \frac{3 x + 2}{( x + 6 ) ( x - 9 )}

f (x) = 16 - x^{2} + 3 - x

What is the domain of 1/(2xsqrt(4+ln(x))) ?
The domain of 1/(2xsqrt(4+ln(x))) is x> 1/(e^4)