What is the domain of 4tan(2x+pi/3)-1 ?

The domain of 4tan(2x+pi/3)-1 is pi/2 n<= x< pi/(12)+pi/2 n\lor pi/(12)+pi/2 n<x< pi/2+pi/2 n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 4tan(2x+pi/3)-1

domain

4 tan (2 x + \frac{π}{3}) - 1

\frac{π}{2} n \leq x < \frac{π}{12} + \frac{π}{2} n or \frac{π}{12} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

Interval Notation

[\frac{π}{2} n, \frac{π}{12} + \frac{π}{2} n) \cup (\frac{π}{12} + \frac{π}{2} n, \frac{π}{2} + \frac{π}{2} n)

Solution steps

Take the denominator(s) of

4 tan (2 x + \frac{π}{3}) - 1

and compare to zero:

x = \frac{π}{12} + \frac{π}{2} n

Periodicity of

4 tan (2 x + \frac{π}{3}) - 1 : \frac{π}{2}

Combine period:

\frac{π}{2} n \leq x < \frac{π}{2} + \frac{π}{2} n

and undefined points.

The domain is

\frac{π}{2} n \leq x < \frac{π}{12} + \frac{π}{2} n or \frac{π}{12} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

4 x - 6, x = - 2

f (x) = sec^{\frac{1}{2}} (x)

\frac{x - 12}{5}

f (x) = \frac{1 - 9 - x ^{2}}{∣ x - 3 ∣ - 1}

\frac{2 x + 1}{2 x + 4}

What is the domain of 4tan(2x+pi/3)-1 ?
The domain of 4tan(2x+pi/3)-1 is pi/2 n<= x< pi/(12)+pi/2 n\lor pi/(12)+pi/2 n<x< pi/2+pi/2 n