What is the domain of f(x)=(y+10)/(sqrt(y-1)) ?

The domain of f(x)=(y+10)/(sqrt(y-1)) is y>1

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domain of f(x)=(y+10)/(sqrt(y-1))

domain

f (x) = \frac{y + 10}{y - 1}

y > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

y \geq 1

Find undefined (singularity) points:

y = 1

Combine real regions and undefined points for final function domain

y > 1

(ln (x))^{3}

(ln (x))^{2}

f (x) = 2 (\frac{1}{10})^{x}

\frac{2}{x} - 5

f (x) = - 4 x + 6

What is the domain of f(x)=(y+10)/(sqrt(y-1)) ?
The domain of f(x)=(y+10)/(sqrt(y-1)) is y>1