What is the domain of f(x)=\sqrt[4]{x(x^2+5)} ?

The domain of f(x)=\sqrt[4]{x(x^2+5)} is x>= 0

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domain of f(x)=\sqrt[4]{x(x^2+5)}

domain

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

g (x) = (2 x)^{2} - 3

\frac{x + 1}{x - 1}

2 - x^{2}

f (x) = \frac{x + 2}{x ^{2} - 6 x + 9}

\frac{3 x}{7 x - 5}

What is the domain of f(x)=\sqrt[4]{x(x^2+5)} ?
The domain of f(x)=\sqrt[4]{x(x^2+5)} is x>= 0