What is the domain of f(x)=1-sqrt(y+1) ?

The domain of f(x)=1-sqrt(y+1) is y>=-1

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domain of f(x)=1-sqrt(y+1)

domain

f (x) = 1 - y + 1

y \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

y \geq - 1

The function domain

y \geq - 1

\frac{( x - 7 )}{( x + 4 )}

f (x) = \frac{x + 6}{x ^{2} + x - 30}

ln (x^{2} + 25)

f (x) = ∣ x - 2 ∣ + ∣ x + 2 ∣

f (x) = \frac{- 5 x - 7}{4 - x}

What is the domain of f(x)=1-sqrt(y+1) ?
The domain of f(x)=1-sqrt(y+1) is y>=-1