What is the domain of f(x)= 2/(x^2+3x-4) ?

The domain of f(x)= 2/(x^2+3x-4) is x 1

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domain of f(x)= 2/(x^2+3x-4)

domain

f (x) = \frac{2}{x ^{2} + 3 x - 4}

x < - 4 or - 4 < x < 1 or x > 1

Interval Notation

(- \infty, - 4) \cup (- 4, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 4

The function domain

x < - 4 or - 4 < x < 1 or x > 1

f (x) = \frac{1}{x - 2 - 1 - 2}

f (x) = \frac{3}{( x ^{2} - 16 )}

f (x) = \frac{1}{x + 2}

\frac{x ^{2} - 1}{x ^{3}}

ln (x - 1) + 2

What is the domain of f(x)= 2/(x^2+3x-4) ?
The domain of f(x)= 2/(x^2+3x-4) is x<-4\lor-4<x<1\lor x>1