What is the domain of (sqrt(x+1))/(x^2) ?

The domain of (sqrt(x+1))/(x^2) is -1 0

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domain of (sqrt(x+1))/(x^2)

domain

\frac{x + 1}{x ^{2}}

- 1 \leq x < 0 or x > 0

Interval Notation

[- 1, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or x > 0

f (x) = e^{x} + ln (x)

f (x) = \frac{x + 12}{x ^{2} + 9 x - 22}

f (x) = \frac{x}{( x + 4 )}

x^{2} - 1 + 15

\frac{x - 5}{x ^{2} - 2 x - 35}

What is the domain of (sqrt(x+1))/(x^2) ?
The domain of (sqrt(x+1))/(x^2) is -1<= x<0\lor x>0