What is the domain of f(x)=sqrt(3x^2-27) ?

The domain of f(x)=sqrt(3x^2-27) is x = 3

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domain of f(x)=sqrt(3x^2-27)

domain

f (x) = 3 x^{2} - 27

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

\frac{x ^{3} + 5 x ^{2}}{7 x ^{2} - 2}

f (x) = \frac{2}{( \frac{2}{x - 7} ) - 7}

f (x) = \frac{x}{2 x - ∣ x ∣}

f (x) = x^{2} + 8 x - 9

f (x) = \frac{6 x}{x ^{2} - 14 x + 45}

What is the domain of f(x)=sqrt(3x^2-27) ?
The domain of f(x)=sqrt(3x^2-27) is x<=-3\lor x>= 3