What is the asymptotes of f(x)=((x^2+1))/((x^2-1)) ?

The asymptotes of f(x)=((x^2+1))/((x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=1

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asymptotes of f(x)=((x^2+1))/((x^2-1))

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{( x ^{2} - 1 )}

Vertical : x = - 1, x = 1, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 1

h (x) = \frac{2}{2 x + 1}

f (x) = sec (\frac{π x}{2})

f (x) = 8 tan (π x)

(2, - 4), (6, 4)

f (x) = 2 x^{2} + 4 x + 3

What is the asymptotes of f(x)=((x^2+1))/((x^2-1)) ?
The asymptotes of f(x)=((x^2+1))/((x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=1