What is the domain of sqrt(2x^2+5x-12) ?

The domain of sqrt(2x^2+5x-12) is x = 3/2

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domain of sqrt(2x^2+5x-12)

domain

2 x^{2} + 5 x - 12

x \leq - 4 or x \geq \frac{3}{2}

Interval Notation

(- \infty, - 4] \cup [\frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq \frac{3}{2}

The function domain

x \leq - 4 or x \geq \frac{3}{2}

f (x) = \frac{sin ( x ) + 1}{x - 1}

f (x) = lo g_{10} (\frac{x - 3}{2})

(x^{2} + x)^{2} + (x^{2} + x)

2 x + x^{2}

f (x) = 5 x^{2} + 9 x - 8

What is the domain of sqrt(2x^2+5x-12) ?
The domain of sqrt(2x^2+5x-12) is x<=-4\lor x>= 3/2