What is the domain of f(x)=sqrt(6x^2-6) ?

The domain of f(x)=sqrt(6x^2-6) is x = 1

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domain of f(x)=sqrt(6x^2-6)

domain

f (x) = 6 x^{2} - 6

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

f (x) = \frac{x ^{2} - 3}{5 x ^{2} + 2 x + 1}

f (x) = \frac{2 x + 4}{x ^{4} + 81}

f (x) = \frac{4 x + 2}{x ^{2} + 7 x - 8}

3 5 - x - 8

\frac{( ln ( x - 2 ) - 2 )}{4}

What is the domain of f(x)=sqrt(6x^2-6) ?
The domain of f(x)=sqrt(6x^2-6) is x<=-1\lor x>= 1