What is the domain of g(x)=(x-3)/(x+1) ?

The domain of g(x)=(x-3)/(x+1) is x -1

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domain of g(x)=(x-3)/(x+1)

domain

g (x) = \frac{x - 3}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

lo g_{10} (x)

- \frac{7}{3} x + \frac{35}{3}

f (x) = x^{2} - 4 x^{2}

f (x) = \frac{x ^{2} - 4 x + 2}{x}

What is the domain of g(x)=(x-3)/(x+1) ?
The domain of g(x)=(x-3)/(x+1) is x<-1\lor x>-1