What is the domain of f(x)=sqrt(2x^2-11x+12) ?

The domain of f(x)=sqrt(2x^2-11x+12) is x = 4

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domain of f(x)=sqrt(2x^2-11x+12)

domain

f (x) = 2 x^{2} - 11 x + 12

x \leq \frac{3}{2} or x \geq 4

Interval Notation

(- \infty, \frac{3}{2}] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq \frac{3}{2} or x \geq 4

The function domain

x \leq \frac{3}{2} or x \geq 4

y = \frac{x - 3}{( x + 7 ) ( x - 13 )}

f (x) = \frac{9 x}{x + 2}

f (x) = (- 1.4)

\frac{5 x - 3}{2 x + 3}

\frac{3 x - 4}{5 x + 6}

What is the domain of f(x)=sqrt(2x^2-11x+12) ?
The domain of f(x)=sqrt(2x^2-11x+12) is x<= 3/2 \lor x>= 4