What is the domain of f(x)=sqrt(x)^2 ?

The domain of f(x)=sqrt(x)^2 is x>= 0

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domain of f(x)=sqrt(x)^2

domain

f (x) = x^{2}

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = ∣ 8 - 4 x ∣

lo g_{10} (5 - x)

f (x) = \frac{- 2 x + 3}{5 x + 1}

3 x^{3} - 25 x^{2} + 64 x - 48

\frac{3 x - 4}{x ^{3} - 9 x}