What is the inverse of f(x)=x^2+5x ?

The inverse of f(x)=x^2+5x is (-5+sqrt(25+4x))/2 ,(-5-sqrt(25+4x))/2

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inverse of f(x)=x^2+5x

inverse

f (x) = x^{2} + 5 x

\frac{- 5 + 25 + 4 x}{2}, \frac{- 5 - 25 + 4 x}{2}

Solution steps

y = x^{2} + 5 x

Replace

x

with

y

x = y^{2} + 5 y

Solve for

y, x = y^{2} + 5 y

\frac{- 5 + 25 + 4 x}{2}, \frac{- 5 - 25 + 4 x}{2}

f (x) = \frac{1}{x} - 1

f (x) = 5 + 4 x - x^{2}

\frac{x + 2}{x ^{2} - 2 x - 3}

f (x) = 3^{x - 1}

f (x) = 4 x - 20

What is the inverse of f(x)=x^2+5x ?
The inverse of f(x)=x^2+5x is (-5+sqrt(25+4x))/2 ,(-5-sqrt(25+4x))/2