What is the domain of 1/(1+sqrt(x-2)) ?

The domain of 1/(1+sqrt(x-2)) is x>= 2

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domain of 1/(1+sqrt(x-2))

domain

\frac{1}{1 + x - 2}

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

\frac{1}{x ^{2} + 3 x - 28}

x^{2} - 6 x - y + 5 = 0

f (x) = x + 1 + 1

\frac{x + 27}{\frac{1}{26 - x}}

x - x^{2}