What is the domain of f(x)=-6/(64-x^2) ?

The domain of f(x)=-6/(64-x^2) is x 8

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domain of f(x)=-6/(64-x^2)

domain

f (x) = - \frac{6}{64 - x ^{2}}

x < - 8 or - 8 < x < 8 or x > 8

Interval Notation

(- \infty, - 8) \cup (- 8, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 8

The function domain

x < - 8 or - 8 < x < 8 or x > 8

f (x) = ∣ x - 8 ∣

\frac{x + 1}{x - 1}

f (x) = \frac{5 x + 2}{12} + x

f (x) = - 2 x^{2} + x

x^{2} - 5 x + 4

What is the domain of f(x)=-6/(64-x^2) ?
The domain of f(x)=-6/(64-x^2) is x<-8\lor-8<x<8\lor x>8