What is the domain of f(x)= 1/4 (x^3+6x^2+5x-4) ?

The domain of f(x)= 1/4 (x^3+6x^2+5x-4) is -infinity <x<infinity

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domain of f(x)= 1/4 (x^3+6x^2+5x-4)

domain

f (x) = \frac{1}{4} (x^{3} + 6 x^{2} + 5 x - 4)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 12 - 2 x

\frac{5 x - 5}{2 x + 3}

f (x) = 2 x - 3, - 2 \leq x < 1

f (x) = \frac{x ^{2} - 4}{x ^{2} - 2 x}

(\frac{1}{2})^{x} - 1

What is the domain of f(x)= 1/4 (x^3+6x^2+5x-4) ?
The domain of f(x)= 1/4 (x^3+6x^2+5x-4) is -infinity <x<infinity