What is the domain of f(x)=log_{4}(3x-12)+8 ?

The domain of f(x)=log_{4}(3x-12)+8 is x>4

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domain of f(x)=log_{4}(3x-12)+8

domain

f (x) = lo g_{4} (3 x - 12) + 8

x > 4

Interval Notation

(4, \infty)

Solution steps

Find positive values for logs:

x > 4

The function domain

x > 4

f (x) = \frac{1}{x ^{2} - 7 x + 13}

f (x) = 3 - x, 2 \leq x < 5

f (x) = (arcsin (x))

f (x) = x^{3} - 25 x

f (x) = \frac{x - 4}{x - 2}

What is the domain of f(x)=log_{4}(3x-12)+8 ?
The domain of f(x)=log_{4}(3x-12)+8 is x>4