What is the domain of (sqrt(2x+14))/(x^2-49) ?

The domain of (sqrt(2x+14))/(x^2-49) is -7 7

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domain of (sqrt(2x+14))/(x^2-49)

domain

\frac{2 x + 14}{x ^{2} - 49}

- 7 < x < 7 or x > 7

Interval Notation

(- 7, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 7

Find undefined (singularity) points:

x = 7, x = - 7

Combine real regions and undefined points for final function domain

- 7 < x < 7 or x > 7

\frac{1}{6 - 2 x - x ^{2}}

\frac{3 x}{5 x - 6}

\frac{6}{x ^{2} - 4}

lo g_{10} (\frac{x + 7}{x})

y = t^{4}

What is the domain of (sqrt(2x+14))/(x^2-49) ?
The domain of (sqrt(2x+14))/(x^2-49) is -7<x<7\lor x>7