What is the domain of 7/(\frac{x){x+1}} ?

The domain of 7/(\frac{x){x+1}} is x 0

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domain of 7/(\frac{x){x+1}}

domain

\frac{7}{\frac{x}{x + 1}}

x < - 1 or - 1 < x < 0 or x > 0

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 1

The function domain

x < - 1 or - 1 < x < 0 or x > 0

C (x) = \frac{x - 4}{x ^{2} - 25}

\frac{2 x + 1}{3 x - 2}

g (x) = 3 lo g_{4} (x)

\frac{1}{2} - cos (x)

1 - 2 3 - 2 x - x^{2}

What is the domain of 7/(\frac{x){x+1}} ?
The domain of 7/(\frac{x){x+1}} is x<-1\lor-1<x<0\lor x>0