What is the domain of (x^2-1)/(x^3-8) ?

The domain of (x^2-1)/(x^3-8) is x 2

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domain of (x^2-1)/(x^3-8)

domain

\frac{x ^{2} - 1}{x ^{3} - 8}

x < 2 or x > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2

The function domain

x < 2 or x > 2

\frac{\frac{5}{x}}{\frac{5}{x} + 2}

ln (x) + ln (9 - x)

ln (x^{2} + 2 x - 15) + e^{5 - 4 x}

f (x) = 2^{(x + 1)} + 1

What is the domain of (x^2-1)/(x^3-8) ?
The domain of (x^2-1)/(x^3-8) is x<2\lor x>2