What is the domain of f(x)=(x^2-9)/(x^2-x-6) ?

The domain of f(x)=(x^2-9)/(x^2-x-6) is x 3

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domain of f(x)=(x^2-9)/(x^2-x-6)

domain

f (x) = \frac{x ^{2} - 9}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

f (x) = \frac{x}{x ^{3} + 343}

f (x) = \frac{x ^{2} + 5}{4}

x^{4} - 4 x^{3} + 2 x^{2} + x + 4

f (x) = \frac{2 x + 1}{2 x ^{2} - x - 1}

ln (x - 4)

What is the domain of f(x)=(x^2-9)/(x^2-x-6) ?
The domain of f(x)=(x^2-9)/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3