What is the domain of f(x)=(x+9)/(x^2-49) ?

The domain of f(x)=(x+9)/(x^2-49) is x 7

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domain of f(x)=(x+9)/(x^2-49)

domain

f (x) = \frac{x + 9}{x ^{2} - 49}

x < - 7 or - 7 < x < 7 or x > 7

Interval Notation

(- \infty, - 7) \cup (- 7, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 7

The function domain

x < - 7 or - 7 < x < 7 or x > 7

\frac{3}{3 x + 2 - 3 x - 2}

f (x) = 1 - \frac{∣ x + 1 ∣}{∣ x - 1 ∣}

f (x) = \frac{22}{4 x - 15}

f (x) = \frac{x - 8}{x ^{2} + 8 x - 9}

f (x) = lo g_{2} (\frac{3 - 2 x}{1 - x})

What is the domain of f(x)=(x+9)/(x^2-49) ?
The domain of f(x)=(x+9)/(x^2-49) is x<-7\lor-7<x<7\lor x>7