What is the domain of ((x+1)^3)/((x-1)^2) ?

The domain of ((x+1)^3)/((x-1)^2) is x 1

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domain of ((x+1)^3)/((x-1)^2)

domain

\frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = lo g_{e} (x - 5)

p (x) = 3 x + 12

f (x) = \frac{2 - x}{2 + x}

∣ x ∣ + x + 2

y = lo g_{10} (6 + 6 x)

What is the domain of ((x+1)^3)/((x-1)^2) ?
The domain of ((x+1)^3)/((x-1)^2) is x<1\lor x>1