What is the domain of f(x)=sqrt(-3x+9) ?

The domain of f(x)=sqrt(-3x+9) is x<= 3

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domain of f(x)=sqrt(-3x+9)

domain

f (x) = - 3 x + 9

x \leq 3

Interval Notation

(- \infty, 3]

Solution steps

Find non-negative values for radicals:

x \leq 3

The function domain

x \leq 3

f (x) = \frac{2 - x}{x ^{2} - 1}

f (x) = 30 x + 40

y = \frac{4}{9} x - 1

f (x) = - 3 x + 6

f (x) = - 3 x + 3

What is the domain of f(x)=sqrt(-3x+9) ?
The domain of f(x)=sqrt(-3x+9) is x<= 3