What is the domain of f(x)= 4/3 sqrt(x^2-1) ?

The domain of f(x)= 4/3 sqrt(x^2-1) is x = 1

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domain of f(x)= 4/3 sqrt(x^2-1)

domain

f (x) = \frac{4}{3} x^{2} - 1

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

2 - 4 x

f (x) = \frac{x ^{2} + 1}{x ^{2}}

(1 + 5 x)^{\frac{1}{x} + 2}

f (x) = \frac{- 4 x ^{2}}{( x - 4 ) ( x + 2 )}

f (x) = \frac{x - 5}{3 x - 18}

What is the domain of f(x)= 4/3 sqrt(x^2-1) ?
The domain of f(x)= 4/3 sqrt(x^2-1) is x<=-1\lor x>= 1