What is the domain of f(x)=(sqrt(x^2-9)) ?

The domain of f(x)=(sqrt(x^2-9)) is x = 3

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domain of f(x)=(sqrt(x^2-9))

domain

f (x) = (x^{2} - 9)

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

y = 1 0^{2^{x}}

f (x) = \frac{1}{( x - 1 ) ( x - 2 )}

\frac{x ^{2} + 12}{3}

f (5) = (5 - 2) (8 - 5), 2 \leq x \leq 8

f (x) = 6 x^{2} + 48 x + 42

What is the domain of f(x)=(sqrt(x^2-9)) ?
The domain of f(x)=(sqrt(x^2-9)) is x<=-3\lor x>= 3