What is the domain of f(x)=log_{10}(x-1)+8 ?

The domain of f(x)=log_{10}(x-1)+8 is x>1

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domain of f(x)=log_{10}(x-1)+8

domain

f (x) = lo g_{10} (x - 1) + 8

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

The function domain

x > 1

f (x) = \frac{ln ( 3 - 5 x )}{1 - ∣ x + 1 ∣}

f (x) = lo g_{10} (x - 1) + 1

x + 6 - x^{2}

f (x) = \frac{6 x - 1}{( x - 3 ) ( x + 1 )}

(2 x - 1) + 5

What is the domain of f(x)=log_{10}(x-1)+8 ?
The domain of f(x)=log_{10}(x-1)+8 is x>1