What is the domain of y=sqrt(-3x+6) ?

The domain of y=sqrt(-3x+6) is x<= 2

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domain of y=sqrt(-3x+6)

domain

y = - 3 x + 6

x \leq 2

Interval Notation

(- \infty, 2]

Solution steps

Find non-negative values for radicals:

x \leq 2

The function domain

x \leq 2

4 (x - 1)^{\frac{2}{3}}, 0 \leq x \leq 2

\frac{6 x - 7}{7 x + 3}

f (x) = 3 x^{2} - 18 x + 4

f (x) = \frac{10 ( x - 1 )}{2 + ( x - 1 ) ^{2}} + 20

f (x) = \frac{x + 9}{x - 9}