What is the domain of f(x)=sqrt(5-log_{2)(3x-4)} ?

The domain of f(x)=sqrt(5-log_{2)(3x-4)} is 4/3 <x<= 12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(5-log_{2)(3x-4)}

domain

f (x) = 5 - lo g_{2} (3 x - 4)

\frac{4}{3} < x \leq 12

Interval Notation

(\frac{4}{3}, 12]

Solution steps

Find non-negative values for radicals:

\frac{4}{3} < x \leq 12

The function domain

\frac{4}{3} < x \leq 12

f (x) = 4 x + 3 + 5 x - 1

f (x) = \frac{- 4 x}{x ^{2} + x}

lo g_{5} (x + 3) - 2

y = - \frac{1}{x + 7}

\frac{7 x - 5}{- 5 x - 9}

What is the domain of f(x)=sqrt(5-log_{2)(3x-4)} ?
The domain of f(x)=sqrt(5-log_{2)(3x-4)} is 4/3 <x<= 12