What is the domain of f(x)=log_{2}((1-x)(2x-3)) ?

The domain of f(x)=log_{2}((1-x)(2x-3)) is 1<x< 3/2

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domain of f(x)=log_{2}((1-x)(2x-3))

domain

f (x) = lo g_{2} ((1 - x) (2 x - 3))

1 < x < \frac{3}{2}

Interval Notation

(1, \frac{3}{2})

Solution steps

Find positive values for logs:

1 < x < \frac{3}{2}

The function domain

1 < x < \frac{3}{2}

f (x) = 2^{- x} + 2

f (x) = \frac{5}{( x + 6 )}

y = \frac{2 x ^{2} - 2 x + 3}{2 x ^{2} - 2 x + 2}

f (- 1) = x^{2} + 4 x - 3

f (x) = \frac{1}{2 x ^{2} - 5 x}

What is the domain of f(x)=log_{2}((1-x)(2x-3)) ?
The domain of f(x)=log_{2}((1-x)(2x-3)) is 1<x< 3/2