What is the domain of g(x)=(x-1)/(x^2-8x-9) ?

The domain of g(x)=(x-1)/(x^2-8x-9) is x 9

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domain of g(x)=(x-1)/(x^2-8x-9)

domain

g (x) = \frac{x - 1}{x ^{2} - 8 x - 9}

x < - 1 or - 1 < x < 9 or x > 9

Interval Notation

(- \infty, - 1) \cup (- 1, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = - 1

The function domain

x < - 1 or - 1 < x < 9 or x > 9

f (x) = 2^{- x} - 2

f (x) = 2^{- x} - 1

f (x) = lo g_{4} (x^{2} - 64)

\frac{1}{6} arctan (x)

What is the domain of g(x)=(x-1)/(x^2-8x-9) ?
The domain of g(x)=(x-1)/(x^2-8x-9) is x<-1\lor-1<x<9\lor x>9