What is the domain of (x^2+1)/(x-1)+\sqrt[3]{x} ?

The domain of (x^2+1)/(x-1)+\sqrt[3]{x} is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (x^2+1)/(x-1)+\sqrt[3]{x}

domain

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = \frac{2 x - 3}{x ^{2} - 3 x + 2}

f (x) = \frac{19 x}{x + 20}

f (x) = \frac{x - 2}{x x - 4}

\frac{x ^{2} + 2 x - 3}{x + 1}

f (x) = \frac{x + 10}{6 + x}

What is the domain of (x^2+1)/(x-1)+\sqrt[3]{x} ?
The domain of (x^2+1)/(x-1)+\sqrt[3]{x} is x<1\lor x>1