What is the domain of f(x)=sqrt(-2x^2+5x-3) ?

The domain of f(x)=sqrt(-2x^2+5x-3) is 1<= x<= 3/2

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domain of f(x)=sqrt(-2x^2+5x-3)

domain

f (x) = - 2 x^{2} + 5 x - 3

1 \leq x \leq \frac{3}{2}

Interval Notation

[1, \frac{3}{2}]

Solution steps

Find non-negative values for radicals:

1 \leq x \leq \frac{3}{2}

The function domain

1 \leq x \leq \frac{3}{2}

- x^{2} - 1

y = \frac{1}{4 - 2 - x}

f (x) = - \frac{x ^{2} - 50}{x ^{2} - 25}

f (x) = 2 - x - 2

f (x) = x e^{x^{2}} sin (e^{x^{2}})

What is the domain of f(x)=sqrt(-2x^2+5x-3) ?
The domain of f(x)=sqrt(-2x^2+5x-3) is 1<= x<= 3/2