What is the domain of f(x)=(63-7x)/(9x-88) ?

The domain of f(x)=(63-7x)/(9x-88) is x 88/9

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domain of f(x)=(63-7x)/(9x-88)

domain

f (x) = \frac{63 - 7 x}{9 x - 88}

x < \frac{88}{9} or x > \frac{88}{9}

Interval Notation

(- \infty, \frac{88}{9}) \cup (\frac{88}{9}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{88}{9}

The function domain

x < \frac{88}{9} or x > \frac{88}{9}

f (x) = \frac{1}{4} ∣ x + 1 ∣

f (x) = - (x + 4)^{2} - 2

f (x) = - (x + 4)^{2} - 3

f (x) = \frac{1}{- x + 1 ^{2} + 2}

f (x) = \frac{- 2 ( x + 2 )}{5 x ^{2} - 4 x - 9}

What is the domain of f(x)=(63-7x)/(9x-88) ?
The domain of f(x)=(63-7x)/(9x-88) is x< 88/9 \lor x> 88/9