What is the inverse of f(x)=(2x-3)/(7x+5) ?

The inverse of f(x)=(2x-3)/(7x+5) is (-3-5x)/(7x-2)

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inverse of f(x)=(2x-3)/(7x+5)

inverse

f (x) = \frac{2 x - 3}{7 x + 5}

\frac{- 3 - 5 x}{7 x - 2}

Solution steps

y = \frac{2 x - 3}{7 x + 5}

Replace

x

with

y

x = \frac{2 y - 3}{7 y + 5}

Solve for

y, x = \frac{2 y - 3}{7 y + 5}

\frac{- 3 - 5 x}{7 x - 2}

y = - x + 2

(5 x^{2} + 6 x - 2) (x - 5)

f (x) = 1 + (10 + x)^{\frac{1}{2}}

f (x) = \frac{x ^{4} - 1}{x ^{2} - x}

f (x) = \frac{x - 8}{3}

What is the inverse of f(x)=(2x-3)/(7x+5) ?
The inverse of f(x)=(2x-3)/(7x+5) is (-3-5x)/(7x-2)