What is the domain of f(x)=-1/(2(6+x)^{3/2)} ?

The domain of f(x)=-1/(2(6+x)^{3/2)} is x>-6

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domain of f(x)=-1/(2(6+x)^{3/2)}

domain

f (x) = - \frac{1}{2 ( 6 + x ) ^{\frac{3}{2}}}

x > - 6

Interval Notation

(- 6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = - 6

Combine real regions and undefined points for final function domain

x > - 6

\frac{16 - x ^{2} - 4}{2 - ∣ x - 3 ∣}

f (x) = 2 - 11 x

\frac{5 x - 6}{6 x + 1}

f (x) = lo g_{5} (\frac{x ^{2} - 9}{x + 3})

\frac{ln ( 3 \frac{x}{10} ) - 4}{3}

What is the domain of f(x)=-1/(2(6+x)^{3/2)} ?
The domain of f(x)=-1/(2(6+x)^{3/2)} is x>-6