What is the domain of ((sqrt(25-x^2)))/(sqrt(x+1)) ?

The domain of ((sqrt(25-x^2)))/(sqrt(x+1)) is -1<x<= 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of ((sqrt(25-x^2)))/(sqrt(x+1))

domain

\frac{( 25 - x ^{2} )}{x + 1}

- 1 < x \leq 5

Interval Notation

(- 1, 5]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 5

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

- 1 < x \leq 5

f (x) = \frac{x - 2}{( x + 5 ) ( x + 2 )}

\frac{1}{11 ( \frac{1}{x ^{2}} ) - 1}

f (x) = 18 x + 63

sin (4 x^{2} - 6 x - 2)

f (x) = 6500 x^{2} + 4

What is the domain of ((sqrt(25-x^2)))/(sqrt(x+1)) ?
The domain of ((sqrt(25-x^2)))/(sqrt(x+1)) is -1<x<= 5