What is the domain of (1/(2x^2+3))+(sqrt(3x-4)) ?

The domain of (1/(2x^2+3))+(sqrt(3x-4)) is x>= 4/3

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domain of (1/(2x^2+3))+(sqrt(3x-4))

domain

(\frac{1}{2 x ^{2} + 3}) + (3 x - 4)

x \geq \frac{4}{3}

Interval Notation

[\frac{4}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{4}{3}

The function domain

x \geq \frac{4}{3}

y = \frac{2}{5 x + 3}

(x - 2)^{2} (\frac{2 x + 4}{x})

f (x) = \frac{18 x}{106 x}

f (x) = 18 x + 18

\frac{2 x ^{2} - 1}{5}

What is the domain of (1/(2x^2+3))+(sqrt(3x-4)) ?
The domain of (1/(2x^2+3))+(sqrt(3x-4)) is x>= 4/3