What is the domain of y=\sqrt[3]{(3x+2)/(x+1)} ?

The domain of y=\sqrt[3]{(3x+2)/(x+1)} is x -1

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domain of y=\sqrt[3]{(3x+2)/(x+1)}

domain

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = 2 x + 2 x

f (x) = \frac{( 2 x - 5 )}{( x ^{2} - 3 x )}

\frac{4 x}{e ^{4 x}}

lo g_{3} (x + 9) + 6

f (x) = (3 x + 5)

What is the domain of y=\sqrt[3]{(3x+2)/(x+1)} ?
The domain of y=\sqrt[3]{(3x+2)/(x+1)} is x<-1\lor x>-1