What is the domain of 1/((\frac{9){x-2})-3} ?

The domain of 1/((\frac{9){x-2})-3} is x 5

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domain of 1/((\frac{9){x-2})-3}

domain

\frac{1}{( \frac{9}{x - 2} ) - 3}

x < 2 or 2 < x < 5 or x > 5

Interval Notation

(- \infty, 2) \cup (2, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = 2

The function domain

x < 2 or 2 < x < 5 or x > 5

\frac{x + 4}{- x - 3}

f (x) = x - 4, - 1 < x \leq 3

\frac{x ^{2} - 25}{x ^{2} - x - 20}

F (x) = \frac{x - 9}{x ^{3} + 4 x}

\frac{4}{e - e ^{\frac{2}{x + 2}}}

What is the domain of 1/((\frac{9){x-2})-3} ?
The domain of 1/((\frac{9){x-2})-3} is x<2\lor 2<x<5\lor x>5