What is the domain of f(x)=((sqrt(x-4)))/(x-8) ?

The domain of f(x)=((sqrt(x-4)))/(x-8) is 4 8

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domain of f(x)=((sqrt(x-4)))/(x-8)

domain

f (x) = \frac{( x - 4 )}{x - 8}

4 \leq x < 8 or x > 8

Interval Notation

[4, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

4 \leq x < 8 or x > 8

g (x) = \frac{x ^{2}}{x ^{2} + 4}

f (x) = 7 + 4 x

\frac{( \frac{( 2 x - 1 )}{2} )}{( \frac{( x + 2 )}{3} )}

f (x) = ln (17 x)

f (x) = \frac{- 7}{x - 9}

What is the domain of f(x)=((sqrt(x-4)))/(x-8) ?
The domain of f(x)=((sqrt(x-4)))/(x-8) is 4<= x<8\lor x>8