What is the domain of f(x)= 2/(sqrt(x^2-1)) ?

The domain of f(x)= 2/(sqrt(x^2-1)) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 2/(sqrt(x^2-1))

domain

f (x) = \frac{2}{x ^{2} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

\frac{x ( x - 2 ) ^{2}}{( x + 6 ) ^{3}}

x^{4} + 3

y = x + 5 - 2

f (x) = \frac{( 2 x - 5 )}{( x - 1 )}

f (x) = \frac{x ^{3} - 2 x}{x ( - x - 6 )}

What is the domain of f(x)= 2/(sqrt(x^2-1)) ?
The domain of f(x)= 2/(sqrt(x^2-1)) is x<-1\lor x>1