What is the domain of y= 2/pi arcsin(1-x^2)+pi/3 ?

The domain of y= 2/pi arcsin(1-x^2)+pi/3 is -sqrt(2)<= x<= sqrt(2)

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domain of y= 2/pi arcsin(1-x^2)+pi/3

domain

y = \frac{2}{π} arcsin (1 - x^{2}) + \frac{π}{3}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find known functions domain restrictions:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

f (x) = \frac{x - 3}{x + 3}

f (x) = 3 cos (x + (\frac{( 1 )}{( 2 )}))

f (t) = \frac{x - 5}{2 x + 4}

(4 x + 3) + (x - 9)

y = ∣ x - 1 ∣

What is the domain of y= 2/pi arcsin(1-x^2)+pi/3 ?
The domain of y= 2/pi arcsin(1-x^2)+pi/3 is -sqrt(2)<= x<= sqrt(2)